If a current of 2 mA is applied for 10 minutes during iontophoresis, what is the dose in mA-min?

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Multiple Choice

If a current of 2 mA is applied for 10 minutes during iontophoresis, what is the dose in mA-min?

Explanation:
In iontophoresis, the dose is the total electrical charge delivered, expressed as milliampere-minutes (mA-min). It’s found by multiplying the current (in milliamperes) by the time (in minutes). So a current of 2 mA applied for 10 minutes yields 2 × 10 = 20 mA-min. This is the amount of charge delivered. If either the current or the time were increased, the dose would scale proportionally (for example, 1 mA for 10 minutes would be 10 mA-min, or 2 mA for 20 minutes would be 40 mA-min).

In iontophoresis, the dose is the total electrical charge delivered, expressed as milliampere-minutes (mA-min). It’s found by multiplying the current (in milliamperes) by the time (in minutes). So a current of 2 mA applied for 10 minutes yields 2 × 10 = 20 mA-min. This is the amount of charge delivered. If either the current or the time were increased, the dose would scale proportionally (for example, 1 mA for 10 minutes would be 10 mA-min, or 2 mA for 20 minutes would be 40 mA-min).

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